(4x^2)+400x-630000=0

Solution for (4x^2)+400x-630000=0 equation:

(4x^2)+400x-630000=0

a = 4; b = 400; c = -630000;
Δ = b2-4ac
Δ = 4002-4·4·(-630000)
Δ = 10240000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10240000}=3200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-3200}{2*4}=\frac{-3600}{8}
=-450
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+3200}{2*4}=\frac{2800}{8}
=350
$